Half-Space and the Need for Boundary
Every manifold we have constructed so far has been locally modeled on \(\mathbb{R}^n\), with no edges and no rim.
That list runs from spheres, projective spaces and tori to the
Grassmannians
and the topological manifolds
of the opening pages. Near every point, such a manifold looks like all of Euclidean space. Yet many of the most
natural geometric objects do have edges. A closed interval \([a, b] \subseteq \mathbb{R}\) has its two endpoints.
A closed disk in the plane has its bounding circle. A closed hemisphere of the sphere \(\mathbb{S}^n\) terminates
at an equatorial \((n-1)\)-sphere. At an endpoint of \([a, b]\), no neighborhood inside the interval is
homeomorphic to an open interval of \(\mathbb{R}\). Every sufficiently small connected open neighborhood is a
half-open interval, with the endpoint sitting on its edge. These spaces are not manifolds in the sense developed
so far, but they are manifolds in a slightly enlarged sense, one that admits a boundary.
We develop this enlarged notion now, as the closing topic of the topological and smooth
foundations, because the boundary is precisely where the most important integral identities of
geometry live. The classical theorems of vector calculus all relate an integral over a region to
an integral over the edge of that region. Green's theorem in the plane, the divergence theorem of
Gauss and the curl theorem of Stokes are the familiar instances. Their common generalization, the
modern Stokes theorem, takes the form
\[
\int_{M} d\omega = \int_{\partial M} \omega,
\]
in which the left-hand side integrates over a manifold and the right-hand side integrates over its boundary
\(\partial M\). For this identity even to be stated, one needs a class of spaces that carry both a smooth
structure in their interior and a well-defined boundary on which the second integral makes sense.
The objects of this page are exactly those spaces. We do not develop integration here, since that
requires the machinery of differential forms, taken up later in the series. The present page
builds the stage on which it will be performed.
The need is not confined to classical analysis. Wherever a domain is constrained, a boundary appears.
Boundary-value problems for partial differential equations are posed on regions whose edges carry the prescribed
data, as in the Dirichlet and Neumann problems and in the free-boundary problems of the calculus of variations.
The integration theory we developed on the measure-theoretic side has
its natural geometric counterpart on manifolds with boundary. The same structure recurs in machine learning and
robotics. A configuration space subject to constraints, such as joint angle limits on an articulated arm, is in
the simplest cases a manifold with boundary rather than a boundaryless one. The
variational autoencoder page's robotic manipulation demonstration
parametrizes a three-degree-of-freedom arm by a triple of joint angles. Once each joint angle is restricted to a
closed interval by a physical joint limit, the admissible configurations fill a product of three closed
intervals. Strictly, a product of closed intervals has corners as well as faces, which places it in the slightly
larger class of manifolds with corners. The manifold series treats that class much later. For now we
record only that boundaries are the rule, not the exception, once domains are constrained.
The Upper Half-Space
Just as a boundaryless \(n\)-manifold is modeled locally on \(\mathbb{R}^n\), a manifold with boundary is modeled
locally on a half-space: the points of \(\mathbb{R}^n\) lying on one side of a hyperplane, together with the
hyperplane itself. Fixing the last coordinate as the one cut off, we obtain the standard local model.
Definition: Closed Upper Half-Space
For \(n \ge 1\), the closed upper half-space \(\mathbb{H}^n \subseteq \mathbb{R}^n\) is the set
\[
\mathbb{H}^n = \bigl\{ (x^1, \ldots, x^n) \in \mathbb{R}^n : x^n \ge 0 \bigr\},
\]
equipped with the subspace topology inherited from \(\mathbb{R}^n\). For \(n = 0\), we set
\(\mathbb{H}^0 = \mathbb{R}^0 = \{0\}\).
The half-space inherits two distinguished subsets from the position of a point relative to the bounding hyperplane.
For \(n \ge 1\), the interior of the half-space consists of the points lying strictly off the
hyperplane,
\[
\operatorname{Int} \mathbb{H}^n = \bigl\{ (x^1, \ldots, x^n) : x^n \gt 0 \bigr\},
\]
and the boundary of the half-space consists of the points lying on it,
\[
\partial \mathbb{H}^n = \bigl\{ (x^1, \ldots, x^n) : x^n = 0 \bigr\}.
\]
The interior \(\operatorname{Int} \mathbb{H}^n\) is an open subset of \(\mathbb{R}^n\), and it is exactly the
topological interior of \(\mathbb{H}^n\) as a subset of \(\mathbb{R}^n\). The boundary
\(\partial \mathbb{H}^n\) is the hyperplane \(\{x^n = 0\}\). Discarding the final
coordinate identifies it with \(\mathbb{R}^{n-1}\), so it is an \((n-1)\)-dimensional Euclidean
space sitting inside \(\mathbb{R}^n\). The degenerate case \(n = 0\) follows the convention above.
Here \(\mathbb{H}^0 = \{0\}\) is a single point with \(\operatorname{Int} \mathbb{H}^0 = \{0\}\)
and \(\partial \mathbb{H}^0 = \varnothing\).
The symbols \(\operatorname{Int}\) and \(\partial\) call for a word of caution, and we return to
it once manifolds enter the picture. As written here, \(\operatorname{Int} \mathbb{H}^n\) and
\(\partial \mathbb{H}^n\) are defined by an inequality on the coordinate \(x^n\). They are subsets
of \(\mathbb{R}^n\) singled out by their position relative to the hyperplane, and this is the
description we use as a local model. A separate matter remains, and it is the central
subtlety of the next section. The interior and boundary of an abstract manifold are defined
intrinsically, without reference to any ambient space, and we must ask whether they can be
detected chart by chart through this model. That they can is the content of an invariance theorem.
Until it is established we keep the half-space picture and the manifold picture notationally
distinct.
Topological Manifolds with Boundary
With the local model in hand, the definition of a manifold with boundary is obtained from the
boundaryless definition by a single change. A neighborhood of a point is now permitted to look
like an open subset of the half-space \(\mathbb{H}^n\), not only an open subset of
\(\mathbb{R}^n\). The Hausdorff and second-countability requirements are unchanged.
Definition: Topological Manifold with Boundary
A topological \(n\)-manifold with boundary is a topological space \(M\) that is
-
Hausdorff
and
second-countable,
and
-
locally Euclidean with boundary: every point \(p \in M\) has an open
neighborhood homeomorphic either to an open subset of \(\mathbb{R}^n\) or to an open subset of
the half-space \(\mathbb{H}^n\).
The phrase "with boundary" is a permission, not a requirement. A point whose neighborhood happens
to be homeomorphic to an open subset of \(\mathbb{R}^n\) is admitted exactly as before. Every
boundaryless \(n\)-manifold is therefore a manifold with boundary in which the boundary turns out
to be empty. We will be able to make that statement precise once the boundary is defined. The
definition deliberately enlarges the class of admissible spaces instead of replacing one
class with another.
Charts and Their Two Types
The chart vocabulary carries over verbatim, with the codomain now allowed to lie in either model space.
Definition: Chart for a Manifold with Boundary
Let \(M\) be a topological \(n\)-manifold with boundary. A chart for \(M\) is a pair
\((U, \varphi)\) where \(U \subseteq M\) is open and \(\varphi\) is a homeomorphism from \(U\) onto
an open subset \(\varphi(U)\) of either \(\mathbb{R}^n\) or \(\mathbb{H}^n\).
Charts split into two kinds according to where their image sits relative to the bounding hyperplane of the
model. The distinction is the engine of the entire theory of the boundary.
Definition: Interior Chart and Boundary Chart
Let \((U, \varphi)\) be a chart for a topological \(n\)-manifold with boundary \(M\).
-
\((U, \varphi)\) is an interior chart if \(\varphi(U)\) is an open subset
of \(\mathbb{R}^n\). This covers the case in which \(\varphi(U)\) is an open subset of
\(\mathbb{H}^n\) disjoint from \(\partial \mathbb{H}^n\), since such a set is also open in
\(\mathbb{R}^n\).
-
\((U, \varphi)\) is a boundary chart if \(\varphi(U)\) is an open subset of
\(\mathbb{H}^n\) with \(\varphi(U) \cap \partial \mathbb{H}^n \ne \varnothing\).
A single subtlety deserves emphasis. By definition of the subspace topology, an open subset of
\(\mathbb{H}^n\) that misses the hyperplane \(\partial \mathbb{H}^n\) is an open subset of
\(\mathbb{R}^n\) as well. A chart with such an image is therefore an interior chart, even when the
half-space was the model we had in mind when writing it down. The classification into interior and
boundary charts is exclusive and exhaustive. A chart image that lies in \(\mathbb{H}^n\) and meets
\(\partial \mathbb{H}^n\) is never open in \(\mathbb{R}^n\), and every chart image is of one kind or
the other. It is precisely the points carried onto \(\partial \mathbb{H}^n\) by some chart
that we are about to single out.
The codomain of a boundary chart often has a standard convenient shape, the half-space analogue of a
coordinate ball.
Definition: Coordinate Half-Ball
A coordinate half-ball is a boundary chart \((U, \varphi)\) whose image is a set of
the form \(B_r(x_0) \cap \mathbb{H}^n\), where \(x_0 \in \partial \mathbb{H}^n\) and \(B_r(x_0)\) is
the open ball of radius \(r\) centered at \(x_0\) in \(\mathbb{R}^n\). Equivalently,
\(\varphi(U)\) is an open ball in \(\mathbb{R}^n\) centered on the hyperplane, intersected
with the half-space.
Interior and Boundary Points
We can now define, intrinsically on \(M\), the two classes of points that the half-space model
distinguishes locally.
Definition: Interior Point, Boundary Point, \(\operatorname{Int} M\), \(\partial M\)
Let \(M\) be a topological \(n\)-manifold with boundary, and let \(p \in M\).
-
\(p\) is an interior point of \(M\) if it lies in the domain of some interior
chart, or in the domain of a boundary chart \((U, \varphi)\) with
\(\varphi(p) \in \operatorname{Int} \mathbb{H}^n\).
-
\(p\) is a boundary point of \(M\) if it lies in the domain of some boundary
chart \((U, \varphi)\) with \(\varphi(p) \in \partial \mathbb{H}^n\).
The set of all boundary points is the boundary of \(M\), denoted \(\partial
M\). The set of all interior points is the interior of \(M\), denoted
\(\operatorname{Int} M\).
The definitions are phrased existentially, in terms of lying in the domain of some chart
of the stated kind, and this is exactly where a difficulty hides. A given point \(p\) may lie in the domains of
many charts at once. Nothing in the definitions, as stated, forbids one chart from presenting \(p\) as an
interior point while another presents the same \(p\) as a boundary point. Were that to happen, the labels
"interior" and "boundary" would not be properties of the point at all, but artifacts of the chart chosen to
view it, and the sets \(\operatorname{Int} M\) and \(\partial M\) would be ill-defined. A theorem
rules this out and shows that the two classes are genuinely intrinsic.
Theorem: Topological Invariance of the Boundary
Let \(M\) be a topological \(n\)-manifold with boundary. No point of \(M\) is simultaneously an interior
point and a boundary point. Consequently \(\operatorname{Int} M\) and \(\partial M\) are disjoint, and
every point of \(M\) belongs to exactly one of them, so that
\[
M = \operatorname{Int} M \sqcup \partial M.
\]
Equivalently, a single chart decides: for every \(p \in M\) and every chart \((U, \varphi)\) whose
domain contains \(p\), we have \(p \in \partial M\) if and only if \((U, \varphi)\) is a boundary chart with
\(\varphi(p) \in \partial \mathbb{H}^n\).
We state this result without proof. The obstruction is genuine. At the purely topological level,
the assertion that an open subset of \(\mathbb{R}^n\) cannot be homeomorphic to a neighborhood of
a point on the edge of \(\mathbb{H}^n\) is a statement about the local topology of Euclidean
space, and it lies beyond what point-set methods can reach. The standard proof uses the machinery
of singular homology, and in particular the local homology groups that distinguish a point of
\(\operatorname{Int} \mathbb{H}^n\) from a point of \(\partial \mathbb{H}^n\). That machinery is
outside the scope of the manifold series at this stage. Remarkably, once a smooth
structure is available, the corresponding statement for smooth charts, that no two smooth charts
disagree about whether a point is interior or boundary, can be proved by elementary calculus with no algebraic topology at all.
That smooth counterpart is the technical climax of this page. One proof requires
homology and the other requires only the chain rule, and the contrast between them is one of the
instructive lessons of the subject.
Two Meanings of the Symbol \(\partial\)
The notation \(\partial M\) collides with another standard use of the same symbol, and the two must be kept
apart. In point-set topology, when a space \(X\) sits inside an ambient space, the topological boundary
of \(X\) is the set of points in the closure of \(X\) that are not in its topological interior.
These are the points that touch both \(X\) and its complement. The manifold boundary just
defined is an intrinsic notion. It depends only on \(M\) as an abstract manifold and not on any
embedding into a larger space. The two need not
coincide, and conflating them is a common source of error.
The closed half-space and the closed unit ball illustrate the agreement, and an interval placed in
the plane illustrates the disagreement. Regarded as a manifold with boundary, \(\mathbb{H}^n\) has
manifold boundary \(\partial \mathbb{H}^n = \{x^n = 0\}\). Regarded as a subset of
\(\mathbb{R}^n\), its topological boundary is the same hyperplane, so here the two notions agree.
The closed unit ball \(\overline{\mathbb{B}}^n \subseteq \mathbb{R}^n\) is a manifold with
boundary whose manifold boundary is the unit sphere \(\mathbb{S}^{n-1}\), and its topological
boundary as a subset of \(\mathbb{R}^n\) is also \(\mathbb{S}^{n-1}\). The two agree again. But
the agreement is not automatic. It requires the manifold to sit in the ambient space as a closed
subset of the same dimension, and either condition can fail. The half-open interval \([0,1)\) inside
\(\mathbb{R}\) has manifold boundary \(\{0\}\) and topological boundary \(\{0, 1\}\), so a failure of
closedness alone already separates the two. The open interval \((0,1)\), viewed as a \(1\)-manifold,
has empty manifold boundary. Viewed as a subset of \(\mathbb{R}^2\) along the \(x\)-axis, it has
empty topological interior and closure \([0,1] \times \{0\}\), so every one of its points is a
topological boundary point. The
manifold boundary is the notion this page concerns, and the symbol \(\partial\) always refers to
it here.
Closed and Open Manifolds
Two further pieces of terminology, both concerning boundaryless manifolds, are conventional in the literature and
worth recording before they appear unannounced. Both invite confusion with the point-set vocabulary of open and
closed sets, and neither has anything to do with it.
Definition: Closed Manifold and Open Manifold
A closed manifold is a compact manifold without boundary. An open manifold
is a noncompact connected manifold without boundary.
The word "closed" here records compactness, not the topological property of being a closed set, and neither a
closed manifold nor an open manifold has any boundary at all. The sphere \(\mathbb{S}^n\) is a closed manifold.
For \(n \geq 1\), the Euclidean space \(\mathbb{R}^n\) and the open ball in it are open manifolds. A closed
interval \([0,1]\), by contrast, is neither. It is compact but does have a boundary, so it is a compact manifold
with boundary and falls under none of this terminology. The terms are useful precisely because the property of
having no boundary, combined with a compactness alternative, organizes much of the global theory of manifolds.
Topological Properties of Manifolds with Boundary
Granting the topological invariance of the boundary, the interior and the boundary of a manifold are
well-defined sets, and we can ask what kind of spaces they are in their own right. The answer is
the cleanest possible one. The interior is a boundaryless manifold of the same
dimension, and the boundary is a boundaryless manifold of one dimension lower. The statement also
records when the boundary is empty and what
happens in the degenerate dimension zero.
Proposition: Structure of the Interior and Boundary
Let \(M\) be a topological \(n\)-manifold with boundary.
-
\(\operatorname{Int} M\) is an open subset of \(M\) and a topological \(n\)-manifold without
boundary.
-
\(\partial M\) is a closed subset of \(M\), and for \(n \ge 1\) it is a topological
\((n-1)\)-manifold without boundary.
-
\(M\) is a topological manifold without boundary if and only if \(\partial M = \varnothing\).
-
If \(n = 0\), then \(\partial M = \varnothing\) and \(M\) is a \(0\)-manifold.
Proof:
(1):
Each interior point lies, by definition, in the domain of a chart carrying it into
\(\operatorname{Int} \mathbb{H}^n\) or into an open subset of \(\mathbb{R}^n\). Shrinking that
chart's domain to the preimage of a small open ball about the image point produces a
neighborhood of the point consisting entirely of interior points and homeomorphic to an open
subset of \(\mathbb{R}^n\). Hence \(\operatorname{Int} M\) is open in \(M\) and every one of
its points has a Euclidean neighborhood, so it is locally Euclidean without boundary. It
inherits the Hausdorff and second-countability properties from \(M\) as a subspace, and is
therefore a topological \(n\)-manifold without boundary.
(2):
Since \(\partial M = M \setminus \operatorname{Int} M\) by the invariance theorem, and
\(\operatorname{Int} M\) is open, \(\partial M\) is closed in \(M\). For the manifold structure, let
\(p \in \partial M\) lie in a boundary chart \((U, \varphi)\) with \(\varphi(p) \in \partial \mathbb{H}^n\).
By the invariance theorem, read chart by chart, \(\varphi\) carries \(U \cap \partial M\) exactly onto
\(\varphi(U) \cap \partial \mathbb{H}^n\), which is open in \(\partial \mathbb{H}^n\).
Restricting \(\varphi\) to \(U \cap \partial M\) and composing with the identification
\(\partial \mathbb{H}^n \cong \mathbb{R}^{n-1}\) given by dropping the last coordinate yields a
homeomorphism from a neighborhood of \(p\) in \(\partial M\) onto an open subset of \(\mathbb{R}^{n-1}\).
These restricted charts cover \(\partial M\) and exhibit it as locally Euclidean of dimension
\(n-1\) without boundary. With the inherited Hausdorff and second-countability properties,
\(\partial M\) is a topological \((n-1)\)-manifold without boundary.
(3):
If \(\partial M = \varnothing\) then every point is interior, so \(M = \operatorname{Int} M\) is
boundaryless by (1). Conversely, a manifold without boundary has every point covered by a chart into
\(\mathbb{R}^n\), making every point interior, so \(\partial M = \varnothing\) by the invariance
theorem.
(4):
A \(0\)-dimensional model space is a single point: \(\mathbb{R}^0 = \mathbb{H}^0 = \{0\}\), with
\(\partial \mathbb{H}^0 = \varnothing\) by convention. Every chart on a \(0\)-manifold therefore carries
its point into \(\operatorname{Int} \mathbb{H}^0\), so no point can be a boundary point and
\(\partial M = \varnothing\).
The relation \(\partial M = M \setminus \operatorname{Int} M\) used in part (2) is exactly the disjoint-union
decomposition supplied by the invariance theorem. Without that theorem, a boundary point might
also be an interior point, so \(\partial M\) could be strictly larger than
\(M \setminus \operatorname{Int} M\), and the closedness of \(\partial M\) would not follow. The same
theorem, in its chart-by-chart form, is what lets a single chart
decide whether a point lies on the boundary, as in the manifold structure on \(\partial M\) just
constructed. Every later argument that reads the boundary off from one chart rests on it.
Carrying the Topological Properties Across
The properties established earlier for boundaryless manifolds all survive the introduction of a
boundary. They include the existence of well-behaved bases, local compactness, paracompactness and
connectivity. The reason is structural. Each of those proofs rested on the local model being
Euclidean, and the half-space \(\mathbb{H}^n\) is just as well-behaved a local model as
\(\mathbb{R}^n\). Wherever a coordinate ball was used, a coordinate half-ball serves the same
purpose at boundary points, and the arguments are otherwise unchanged. We collect the results for
the record.
Proposition: Topological Properties with Boundary
Let \(M\) be a topological manifold with boundary. Then:
-
\(M\) has a countable basis of precompact coordinate balls and coordinate half-balls.
-
\(M\) is locally compact.
-
\(M\) is paracompact. More precisely, given an open cover \(\mathcal{U}\) of \(M\) and any
basis \(\mathcal{B}\) for the topology of \(M\), there exists a countable, locally finite
open refinement of \(\mathcal{U}\) consisting of elements of \(\mathcal{B}\).
-
\(M\) is locally path-connected.
-
\(M\) has countably many components, each of which is an open subset of \(M\) and a connected
topological manifold with boundary.
-
The fundamental group of \(M\) is countable.
Each statement is the boundary-aware version of a result proved for manifolds without boundary, and the proofs
require only the substitution of half-balls for balls at boundary points. Statement (1) refines the earlier
basis of precompact coordinate balls
by allowing half-balls in the cover. At boundary charts the single-chart construction in \(\mathbb{R}^n\) is
replaced by the identical construction inside \(\mathbb{H}^n\), and the countable assembly is unchanged.
Statement (2) follows from (1) exactly as before, since
local compactness
needs only one precompact neighborhood at each point, and the half-balls of (1) are precompact. Statement (3),
paracompactness,
is deduced from the basis of (1) and local compactness by the same compact-exhaustion argument, which never
referred to the absence of boundary. Statements (4) and (5) are the
connectivity properties.
Coordinate half-balls, like coordinate balls, are path-connected, since a half-ball is convex and
path-connectedness transfers under the chart homeomorphism. The manifold therefore again has a basis of
path-connected open sets, and the component count is governed by second-countability just as before.
Statement (6), the
countability of the fundamental group,
is of a different character from the rest. It is not a point-set consequence of the basis but a
fact about the algebraic topology of \(M\). Its proof for manifolds without boundary cuts a loop
into finitely many arcs, each confined to a simply connected coordinate ball, and reads off the
loop's class from the countable record of how consecutive arcs meet. Nothing in that argument uses
the absence of a boundary. Coordinate half-balls are convex, hence simply connected, and the cover
by half-balls is countable piece by piece exactly as the cover by balls. The same proof therefore
applies verbatim, with half-balls substituted for balls at boundary charts, and \(\pi_1(M)\) is
countable for a manifold with boundary as well.
Smooth Structures on Manifolds with Boundary
Everything so far has been topological. To do calculus on a manifold with boundary we repeat the construction
that produced
smooth manifolds
from topological ones. We single out a maximal atlas whose transition maps are diffeomorphisms.
There is exactly one new ingredient. Transition maps between boundary charts are maps between open subsets of the half-space
\(\mathbb{H}^n\), not of \(\mathbb{R}^n\), and the
Euclidean
definition of smoothness
we already have applies only to maps on open subsets of \(\mathbb{R}^n\). A subset of \(\mathbb{H}^n\) that meets
the boundary hyperplane is not open in \(\mathbb{R}^n\), so before anything else we must say what it means for a
map defined on such a set to be smooth.
Smoothness on Subsets of the Half-Space
The difficulty is that partial derivatives at a boundary point would have to be one-sided in the last variable,
and a one-sided derivative is a weaker object than a genuine derivative. It sees only the values
of the function on one side. The standard remedy declares a map smooth on a half-space subset exactly when it is the restriction
of an honestly smooth map defined on a full Euclidean neighborhood.
Definition: Smoothness on a Subset of \(\mathbb{H}^n\)
Let \(U \subseteq \mathbb{H}^n\) be open in the subspace topology, and let \(F : U \to \mathbb{R}^k\). The map
\(F\) is smooth if for every point \(x \in U\) there exist an open set
\(\widetilde{U} \subseteq \mathbb{R}^n\) containing \(x\) and a smooth map
\(\widetilde{F} : \widetilde{U} \to \mathbb{R}^k\), in the
ordinary Euclidean sense,
that agrees with \(F\) on \(\widetilde{U} \cap U\).
At points of \(U\) lying in \(\operatorname{Int} \mathbb{H}^n\) the condition is ordinary smoothness near the
point. Such a point already has a full neighborhood inside \(U\), on which \(F\), if smooth in the ordinary
sense, serves as its own extension. The definition adds something new only at boundary points of \(U\), where
it demands that \(F\) extend smoothly across the hyperplane to one side. A commonly given alternative
description is that \(F\) is smooth on \(U\) precisely when all partial derivatives of all orders exist
throughout \(U\) and extend continuously up to the boundary. The one-sided derivatives at boundary points then
match the limits of the interior derivatives. That the two descriptions are equivalent is a nontrivial
extension theorem, which we neither prove nor use. We take the extension form as primary because it makes the
chain rule available without one-sided bookkeeping.
That the extension requirement is a genuine restriction, not a formality satisfied by every continuous-looking
function, is shown by a single example. Consider on the half-disk \(\mathbb{B}^2 \cap \mathbb{H}^2\)
the function
\[
g(x, y) = \sqrt{y}, \quad y \ge 0.
\]
It is continuous on its domain and infinitely differentiable at every interior point. But it is not smooth in the
sense just defined: its partial derivative with respect to \(y\),
\[
\frac{\partial g}{\partial y} = \frac{1}{2\sqrt{y}},
\]
diverges as \(y \to 0^+\), so no continuous extension of the \(y\)-derivative to the boundary
exists, and a fortiori no smooth extension of \(g\) to an open neighborhood of any boundary point
in \(\mathbb{R}^2\) can exist. Such an extension would have a finite \(y\)-derivative at the
boundary, which the blow-up forbids.
Smoothness up to the boundary is therefore a real constraint, exactly the one needed to keep the chain rule and
the Jacobian well-behaved at the edge.
Smooth Manifolds with Boundary
With smoothness defined on half-space subsets, the compatibility of charts is defined exactly as before. A
transition map between two charts of a manifold with boundary is a homeomorphism between open subsets of model
spaces, each of which is either \(\mathbb{R}^n\) or \(\mathbb{H}^n\). The Euclidean notion of smoothness applies
when the transition map's domain is open in \(\mathbb{R}^n\) and the half-space notion otherwise, so in every
case we may ask whether it is a diffeomorphism, smooth with smooth inverse.
Definition: Smooth Manifold with Boundary
A smooth manifold with boundary is a topological manifold with boundary \(M\) together with
a maximal atlas of charts into \(\mathbb{R}^n\) or \(\mathbb{H}^n\) whose members are pairwise
smoothly compatible, meaning that the transition map of any two is a diffeomorphism between
the relevant open subsets of model spaces. Smoothness is read in the Euclidean sense when a domain is open in
\(\mathbb{R}^n\) and in the half-space sense otherwise. This maximal atlas is the
smooth structure on \(M\).
This is the
smooth structure of the
boundaryless theory with two adjustments and no others. A chart may now map into \(\mathbb{H}^n\) as well as
\(\mathbb{R}^n\), and the
smooth-compatibility condition
is read with the half-space notion of smoothness wherever the purely Euclidean one does not apply. Suppose there
are no boundary charts, so that every transition is a map between open subsets of \(\mathbb{R}^n\). Only the
Euclidean reading is then used, and the definition reduces exactly to the boundaryless one. A smooth manifold
without boundary is thus the special case of a smooth manifold with boundary in which
\(\partial M = \varnothing\), by part (3) of the
structure of the interior and boundary.
Smooth Charts and Half-Balls
The shape-based refinements of a chart specialize to the boundary setting in the obvious way, mirroring the
smooth coordinate balls
of the boundaryless theory.
Definition: Smooth Coordinate Half-Ball
Let \(M\) be a smooth manifold with boundary. A smooth coordinate half-ball
is a smooth chart \((U, \varphi)\), that is, an element of the smooth structure of \(M\),
whose image is of the form \(B_r(x_0) \cap \mathbb{H}^n\) with \(x_0 \in \partial
\mathbb{H}^n\).
Regular coordinate balls came from a packaging device: a ball sitting with compact closure inside
a strictly larger smooth chart. That packaging has a boundary version, in which the larger chart
is itself a half-ball.
Definition: Regular Coordinate Half-Ball
A subset \(B \subseteq M\) is a regular coordinate half-ball if there exist a smooth
coordinate half-ball \(B'\) with \(\overline{B} \subseteq B'\), a smooth coordinate map
\(\varphi : B' \to \mathbb{H}^n\), and radii \(r \lt r'\) with \(x_0 \in \partial \mathbb{H}^n\) such that
\[
\varphi(B) = B_r(x_0) \cap \mathbb{H}^n, \quad
\varphi(\overline{B}) = \overline{B_r(x_0)} \cap \mathbb{H}^n, \quad
\varphi(B') = B_{r'}(x_0) \cap \mathbb{H}^n.
\]
This is the half-space analogue of a
regular coordinate ball,
and like its boundaryless counterpart it is precompact in \(M\).
The basis result of the boundaryless theory persists as well.
Proposition: Basis of Regular Coordinate Balls and Half-Balls
Just as every smooth manifold has a
countable basis of regular coordinate balls,
every smooth manifold with boundary has a countable basis consisting of
regular coordinate balls at interior points and regular coordinate half-balls at boundary points.
The proof is the smooth refinement of the topological basis result of the previous section, adapted
exactly as the boundaryless basis-of-regular-balls argument was adapted from its topological
predecessor. Every chart in the construction is required to lie in the smooth structure, and at
boundary points the half-ball model replaces the ball. We will not rewrite that argument here, since
it differs from the one already given only by this substitution.
Open Submanifolds with Boundary
One further construction of the boundaryless theory carries over, and it is the one the pages
ahead will lean on most heavily. Passing to an open subset costs nothing, and it costs nothing at
the boundary either.
Definition: Open Submanifold with Boundary
Let \(M\) be a
smooth \(n\)-manifold with boundary
with smooth structure \(\mathcal{A}\), and let \(U \subseteq M\) be an open subset. The collection
\[
\mathcal{A}_U = \{(V, \varphi) \in \mathcal{A} : V \subseteq U\}
\]
is a smooth atlas on \(U\), and the smooth structure it determines makes \(U\) into a smooth
\(n\)-manifold with boundary, whose boundary is \(\partial U = U \cap \partial M\). Equipped
with the subspace topology and this smooth structure, \(U\) is called an open
submanifold with boundary of \(M\). When \(U \subseteq \operatorname{Int} M\) the
boundary of \(U\) is empty and \(U\) is an
open submanifold
in the earlier sense; in particular \(\operatorname{Int} M\) is an open submanifold of \(M\)
without boundary.
That \(U\) is a topological \(n\)-manifold with boundary is immediate. Hausdorffness and second
countability are inherited by subspaces, and a point of \(U\) has, inside \(U\), a neighborhood
modeled on an open subset of \(\mathbb{R}^n\) or of \(\mathbb{H}^n\), namely the intersection with
\(U\) of any chart domain around it.
The rest of the verification is the one already carried out in the boundaryless case. Every point
of \(U\) lies in the domain of some smooth chart \((W, \varphi)\) for
\(M\), and the restriction of that chart to \(W \cap U\) is smoothly compatible with every chart of
\(\mathcal{A}\), since each restricted transition map is an original transition map restricted to
an open subdomain. By maximality of \(\mathcal{A}\) the restricted chart belongs to
\(\mathcal{A}\), and since \(W \cap U \subseteq U\) it belongs to \(\mathcal{A}_U\). So the charts
of \(\mathcal{A}_U\) cover \(U\), and any two of them are smoothly compatible because they already
lie in \(\mathcal{A}\). The single new feature is that a restricted chart may be a boundary chart,
whose transitions are read in the
half-space sense;
that reading is stable under restriction to an open subdomain exactly as the Euclidean one is,
since a smooth extension across the hyperplane restricts to a smooth extension.
The identity \(\partial U = U \cap \partial M\) concerns the charts through which interior and
boundary points are defined, and it holds because \(U\) is open. A chart of \(U\) is a chart of
\(M\), since an open subset of \(U\) is open in \(M\). Conversely, a chart of \(M\) whose domain
meets \(U\) restricts to a chart of \(U\) on that intersection, with the same coordinates at each
of its points. If \(p \in U\) is a boundary point of \(M\), some boundary chart of \(M\) carries
\(p\) into \(\partial \mathbb{H}^n\), and its restriction to \(U\) is a boundary chart of \(U\)
that does the same, so \(p\) is a boundary point of \(U\). Conversely, a boundary chart of \(U\)
carrying \(p\) into \(\partial \mathbb{H}^n\) is such a chart of \(M\), so a boundary point of
\(U\) is a boundary point of \(M\). Shrinking a domain therefore neither manufactures nor
destroys boundary, and this is what makes open subsets a usable supply of smaller manifolds with
boundary: an argument that is local by nature may be run inside a single chart domain without
leaving the category. If \(U \subseteq \operatorname{Int} M\), then
\(\partial U = U \cap \partial M = \varnothing\) by the
topological invariance of the boundary,
and no chart of \(\mathcal{A}_U\) is a boundary chart, since such a chart would carry some point of
\(U\) into \(\partial \mathbb{H}^n\), making it a point of \(\partial U\). Every chart of \(\mathcal{A}_U\) then
has image open in \(\mathbb{R}^n\), and \(\mathcal{A}_U\) is a smooth structure in the boundaryless
sense.
Product and Smooth Invariance
Two results close the theory. The first records how the boundary behaves under products. The
second is the smooth counterpart of the invariance theorem stated earlier, and it is the technical
high point of the page. Where
the topological invariance required the machinery of algebraic topology, the smooth invariance falls to the chain
rule and a single fact about smooth maps with invertible derivative.
Products
Taking products of manifolds with boundary requires care, and the care is exactly the issue of corners. The
product of two closed half-lines is a closed quarter-plane, whose edge is not a smooth hypersurface but a pair of
rays meeting at a right angle. To stay within the category of manifolds with boundary, one must restrict products
so that at most one factor has a boundary.
Proposition: Products with a Single Boundary Factor
Let \(M_1, \ldots, M_k\) be smooth manifolds without boundary and let \(N\) be a smooth manifold with boundary.
Then the product \(M_1 \times \cdots \times M_k \times N\) is a smooth manifold with boundary, and
\[
\partial\bigl(M_1 \times \cdots \times M_k \times N\bigr) = M_1 \times \cdots \times M_k \times \partial N.
\]
Proof:
The smooth structure is built from product charts exactly as in the
boundaryless product construction,
with one factor's charts now allowed to be boundary charts into \(\mathbb{H}^m\). Write \(n_i = \dim M_i\)
and \(m = \dim N\). A product chart on \(M_1 \times \cdots \times M_k \times N\) maps into
\(\mathbb{R}^{n_1} \times \cdots \times \mathbb{R}^{n_k} \times E\), where \(E\), either \(\mathbb{R}^m\) or
\(\mathbb{H}^m\), is the model space of the factor chart of \(N\). Write \(n = n_1 + \cdots + n_k\). When
\(E = \mathbb{R}^m\), this product model space is \(\mathbb{R}^{n+m}\). When \(E = \mathbb{H}^m\) and
\(m \geq 1\), the identification \(\mathbb{R}^{n} \times \mathbb{H}^{m} \cong \mathbb{H}^{n+m}\), obtained by
placing the single half-space coordinate last, exhibits the product model space as a half-space of the total
dimension. When \(m = 0\), the factor \(\mathbb{H}^0\) is a point and the product model space is
\(\mathbb{R}^n\). Transition maps are products of the factor transitions. Each factor transition is a
diffeomorphism. A product of smooth maps on open subsets of Euclidean spaces, at most one of which is instead
an open subset of a half-space, is smooth in the Euclidean or the half-space sense as its domain requires,
because a local smooth extension of the half-space factor, taken in product with the Euclidean factors, is a
local smooth extension of the product. The inverse of a product transition is the product of the inverse
factor transitions, so each product transition is a diffeomorphism, and the product charts are smoothly
compatible and assemble into a smooth structure. For the boundary, fix a point \((x, q)\) with
\(x \in M_1 \times \cdots \times M_k\) and \(q \in N\), and a product chart containing it. If the factor
chart of \(N\) is an interior chart, the product chart has image open in \(\mathbb{R}^{n+m}\) and is an
interior chart. If the factor chart is a boundary chart, so is the product chart, and since its half-space
coordinate is that of the \(N\) factor, it carries \((x, q)\) into \(\partial \mathbb{H}^{n+m}\) exactly when
the factor chart carries \(q\) into \(\partial \mathbb{H}^m\). By the
topological invariance of the boundary,
applied chart by chart on the product and on \(N\), the point \((x, q)\) is a boundary point of the product
exactly when \(q \in \partial N\). This is the displayed identity for the boundary.
The single-boundary-factor restriction is essential, not a convenience. The product of two manifolds with boundary
has, along the locus where both boundaries meet, points whose neighborhoods are modeled on a product of two
half-spaces \(\mathbb{H}^n \times \mathbb{H}^m\) rather than on a single half-space. The obstruction is not
topological. The squaring map \(z \mapsto z^2\) of the complex plane carries the closed quarter-plane
homeomorphically onto the closed upper half-plane, so a corner can be flattened away by a homeomorphism. That map has vanishing
derivative at the origin, and no diffeomorphism flattens a corner. We do not prove that last fact
here, since it belongs to the theory of the objects that accommodate corners, the strictly
larger category of manifolds with corners, whose local model is the orthant \(\{x : x^1
\ge 0, \ldots, x^k \ge 0\}\). Their theory is developed much later in the manifold series, and it
is the proper setting for products such as the cube \([0,1]^n\) or the constrained joint-angle
spaces noted at the start of this page.
The Chart Lemma with Boundary
The smooth manifold chart lemma
builds a smooth manifold from a bare set and a collection of candidate charts, but its hypotheses place every
chart image in \(\mathbb{R}^n\). The tangent bundle of a manifold with nonempty boundary, and later the vector
bundles over such a manifold, are built from charts some of whose images are open in a half-space
(\(\mathbb{H}^{2n}\) for the tangent bundle) but not in a Euclidean space. They need the lemma in a form that
admits either model space, with smoothness of transitions read in the
half-space sense wherever a
domain is not open in \(\mathbb{R}^n\). Nothing in the proof depends on which model space a chart uses, and we
record precisely where the argument must be reread.
Lemma: Chart Lemma for Manifolds with Boundary
Let \(M\) be a set, and suppose we are given a collection \(\{U_\alpha\}\) of subsets of \(M\) together with
maps \(\varphi_\alpha : U_\alpha \to E_\alpha\), where each model space \(E_\alpha\) is either \(\mathbb{R}^n\)
or the half-space \(\mathbb{H}^n\), such that the
following properties are satisfied:
-
For each \(\alpha\), \(\varphi_\alpha\) is a bijection between \(U_\alpha\) and an open subset
\(\varphi_\alpha(U_\alpha) \subseteq E_\alpha\).
-
For each \(\alpha\) and \(\beta\), the sets \(\varphi_\alpha(U_\alpha \cap U_\beta)\) and
\(\varphi_\beta(U_\alpha \cap U_\beta)\) are open in \(E_\alpha\) and in \(E_\beta\) respectively.
-
Whenever \(U_\alpha \cap U_\beta \ne \varnothing\), the map
\(\varphi_\beta \circ \varphi_\alpha^{-1} : \varphi_\alpha(U_\alpha \cap U_\beta) \to \varphi_\beta(U_\alpha \cap U_\beta)\)
is smooth, in the Euclidean sense when its domain is open in \(\mathbb{R}^n\) and in the half-space sense
otherwise.
-
Countably many of the sets \(U_\alpha\) cover \(M\).
-
Whenever \(p, q\) are distinct points in \(M\), either there exists some \(U_\alpha\) containing both \(p\) and
\(q\), or there exist disjoint sets \(U_\alpha, U_\beta\) with \(p \in U_\alpha\) and \(q \in U_\beta\).
Then \(M\) has a unique structure of
smooth \(n\)-manifold with boundary
such that each \((U_\alpha, \varphi_\alpha)\) is a smooth chart.
Proof:
We run the proof of the boundaryless chart lemma with \(E_\alpha\) in place of \(\mathbb{R}^n\) throughout, and
check each movement against the two ways a half-space differs from Euclidean space. Its open sets are those of
the subspace topology inherited from \(\mathbb{R}^n\), and smoothness of maps on it is the half-space notion.
Topology.
Take as basis the collection
\[
\mathcal{B} = \{\varphi_\alpha^{-1}(V) : \alpha \text{ any index},\ V \text{ open in } E_\alpha\}.
\]
The cover condition is (4) as before. For the intersection condition, the identity
\[
\varphi_\alpha^{-1}(V) \cap \varphi_\beta^{-1}(W)
= \varphi_\alpha^{-1}\bigl(V \cap (\varphi_\beta \circ \varphi_\alpha^{-1})^{-1}(W)\bigr)
\]
is set-theoretic and holds verbatim. That the set in parentheses is open in \(E_\alpha\) used only two facts.
The transition is continuous, and \(\varphi_\alpha(U_\alpha \cap U_\beta)\) is open in the model space. The
second is (2). For the first, a map that is smooth in the half-space sense is continuous, because near each
point of its domain it agrees with a smooth, hence continuous, map on a Euclidean neighborhood. So
\(\mathcal{B}\) is a basis. The argument that each \(\varphi_\alpha\) is then a homeomorphism onto
\(\varphi_\alpha(U_\alpha)\) uses nothing about the model space beyond its topology and goes through unchanged
from the boundaryless proof.
\(M\) is a topological manifold with boundary.
Each point lies in some \(U_\alpha\), which
\(\varphi_\alpha\) carries homeomorphically onto an open subset of \(\mathbb{R}^n\) or of \(\mathbb{H}^n\).
This is the
locally Euclidean with boundary
condition. The Hausdorff argument from (5) needs only that \(E_\alpha\) is Hausdorff, which \(\mathbb{H}^n\)
inherits from \(\mathbb{R}^n\). For second-countability, the rational-ball basis \(\mathcal{R}\) of
\(\mathbb{R}^n\) used in the boundaryless proof is replaced on a half-space chart by
\(\{R \cap \mathbb{H}^n : R \in \mathcal{R}\}\), a countable basis for the subspace topology of
\(\mathbb{H}^n\). With this substitution the countable basis of \(M\) is assembled from the countably many
charts of (4) exactly as before.
Smooth structure.
Each \((U_\alpha, \varphi_\alpha)\) is now a
chart for a manifold with boundary,
and (3) applied in both orderings makes every transition a diffeomorphism in the sense required by the
definition of a smooth manifold with boundary, so the collection is a smooth atlas in that sense. Enlarging it
to a maximal atlas, and the uniqueness of that enlargement, is the
smooth-structure-from-atlas
argument. That argument manipulates only the compatibility of charts, and it needs compatibility to survive
restriction to open subdomains and composition of transitions. Both hold for half-space smoothness, since a
smooth extension across the hyperplane restricts and composes to a smooth extension. This is the reading
already adopted for open submanifolds with boundary and for products with a single boundary factor above.
Uniqueness.
The topology is the unique one in which each \(\varphi_\alpha\) is a
homeomorphism onto an open subset of \(E_\alpha\), by the argument given above with \(E_\alpha\) for
\(\mathbb{R}^n\), and the smooth structure containing the atlas is then unique as just noted.
Which points of \(M\) end up on the boundary is decided by the given charts. A smooth chart is in
particular a chart, so by the
topological invariance of the boundary,
read chart by chart, a point is a boundary point exactly when some, equivalently every, smooth chart
containing it is a boundary chart carrying it into \(\partial \mathbb{H}^n\). Among smooth charts
alone, the agreement of "some" and "every" is also the
smooth invariance of the boundary
proved next, which needs no homology. In particular \(\partial M\) is the union of the sets
\(\varphi_\alpha^{-1}(\partial \mathbb{H}^n)\) over the indices with \(E_\alpha = \mathbb{H}^n\), and when every
\(E_\alpha\) is \(\mathbb{R}^n\) the boundary is empty and the lemma reduces to the boundaryless one.
Smooth Invariance of the Boundary
We come to the smooth counterpart of the invariance theorem. The interior and
boundary points were defined existentially, a point counting as a boundary point
if some boundary chart sends it to \(\partial \mathbb{H}^n\). The topological invariance
theorem guarantees that the labels are well-defined, and it was stated without proof because it
needs singular homology. For smooth charts the corresponding statement, that no two smooth charts
disagree about whether a point is interior or boundary, is available by elementary means, and we prove it in full.
Theorem: Smooth Invariance of the Boundary
Let \(M\) be a smooth manifold with boundary and let \(p \in M\). If some smooth boundary chart
\((V, \varphi)\) for \(M\) has \(\varphi(p) \in \partial \mathbb{H}^n\), then every smooth chart whose domain
contains \(p\) is a boundary chart carrying \(p\) into \(\partial \mathbb{H}^n\). Equivalently, no point of
\(M\) is presented as a boundary point by one smooth chart and as an interior point by another.
Proof:
The point \(p\) can be presented as an interior point in two ways, by an interior chart or by a boundary
chart \((U, \psi)\) with \(\psi(p) \in \operatorname{Int} \mathbb{H}^n\). The second way reduces to the
first. Replacing \(U\) by \(\psi^{-1}\bigl(\psi(U) \cap \operatorname{Int} \mathbb{H}^n\bigr)\)
leaves a chart whose image is open in \(\mathbb{R}^n\), and the restriction of a smooth chart to an
open subset is smoothly compatible with every chart, hence belongs to the maximal atlas. So we may
work with a smooth interior chart throughout.
Suppose, for contradiction, that \(p\) lies in the domain of a smooth interior chart \((U, \psi)\) and also
in the domain of a smooth boundary chart \((V, \varphi)\) with \(\varphi(p) \in \partial \mathbb{H}^n\). Let
\[
\tau = \varphi \circ \psi^{-1} : \psi(U \cap V) \to \varphi(U \cap V)
\]
be the transition map, a homeomorphism between open subsets of the model spaces. By smooth compatibility of
the two charts, \(\tau\) is smooth in the Euclidean sense and \(\tau^{-1}\) in the half-space sense. Each
agrees locally with a genuinely smooth map defined on an open subset of \(\mathbb{R}^n\).
Write \(x_0 = \psi(p)\) and \(y_0 = \varphi(p) = \tau(x_0)\). Because \(\tau^{-1}\) is smooth at \(y_0\), there
is a neighborhood \(W\) of \(y_0\) in \(\mathbb{R}^n\) and a smooth map \(\eta : W \to \mathbb{R}^n\), in the
ordinary Euclidean sense, agreeing with \(\tau^{-1}\) on \(W \cap \varphi(U \cap V)\). On the other side, since
\((U, \psi)\) is an interior chart, \(\psi(U \cap V)\) is an open subset of \(\mathbb{R}^n\), so there is an
open Euclidean ball \(B\) centered at \(x_0\) and contained in \(\psi(U \cap V)\) on which \(\tau\) is
genuinely smooth. Shrinking \(B\) if necessary, we may assume \(B \subseteq \tau^{-1}(W)\).
On \(B\) the two maps compose to the identity:
\[
\eta \circ \tau\big|_{B} = \tau^{-1} \circ \tau\big|_{B} = \operatorname{id}_{B}.
\]
Differentiating with the chain rule at any \(x \in B\),
\[
D\eta\bigl(\tau(x)\bigr) \circ D\tau(x) = \operatorname{id},
\]
so the square matrix \(D\tau(x)\) has a left inverse and is therefore nonsingular at every \(x \in B\).
We now invoke the one analytic fact the argument needs, the open mapping property of
nonsingular smooth maps. A smooth map between open subsets of \(\mathbb{R}^n\) whose Jacobian
is nonsingular at every point is an open map, so it carries open sets to open sets. This is a
standard consequence of the
inverse function theorem. Nonsingularity of the Jacobian makes the
map a local diffeomorphism at each point, and a local diffeomorphism is locally, hence
globally, open. Applying this to \(\tau\) on \(B\), we find that the image \(\tau(B)\) is an
open subset of \(\mathbb{R}^n\) containing \(y_0 = \varphi(p)\).
This is the contradiction. On the one hand \(\tau(B) \subseteq \varphi(U \cap V) \subseteq
\mathbb{H}^n\), so \(\tau(B)\) is a subset of the half-space. On the other hand \(\tau(B)\) is
open in \(\mathbb{R}^n\) and contains the point \(\varphi(p) \in \partial \mathbb{H}^n\). But
no subset of \(\mathbb{H}^n\) that is open in \(\mathbb{R}^n\) can contain a point of
\(\partial \mathbb{H}^n\). Any \(\mathbb{R}^n\)-open neighborhood of a point with final
coordinate \(x^n = 0\) contains points with \(x^n \lt 0\), which lie outside \(\mathbb{H}^n\).
The assumption that one smooth chart presents \(p\) as an interior point while another presents it as a
boundary point is therefore untenable.
The contrast with the topological invariance theorem stated earlier is worth drawing explicitly, because it
illustrates a recurring theme. A smooth structure, once present, makes available tools far more elementary than
those the bare topology demands. The topological statement says that no homeomorphism from a neighborhood of an
interior point onto a neighborhood of a boundary point can carry the one point to the other. It resists
point-set methods and is proved through the local homology groups of singular homology theory. The smooth
statement just proved needs none of that. The transition map is differentiable, its derivative is forced to be
invertible by the chain rule, and invertibility of the derivative is enough to make a smooth map open. The two
routes differ in cost and, slightly, in reach. Since \(\operatorname{Int} M\) and \(\partial M\) are defined
through all charts, continuous ones included, it is the topological theorem that makes those sets well-defined
and lets any single chart decide membership. The smooth theorem compares smooth charts only. It shows by
elementary means that interior and boundary, as read off from smooth charts, are intrinsic to the smooth
structure, and the topological theorem then identifies what smooth charts see with \(\operatorname{Int} M\) and
\(\partial M\). The elementary smooth argument is one of the first concrete dividends of the smooth structure
built over the course of these pages, and together with the topological theorem it underlies the boundary
integral of the next stage of the theory.