Half-Space and the Need for Boundary
Every manifold we have constructed so far has been locally modeled on \(\mathbb{R}^n\), with no
edges and no rim. That list runs from spheres, projective spaces and tori to the
Grassmannians
and the
topological manifolds
of the opening pages. Near every point, such a manifold looks like all of Euclidean space. Yet
many of the most natural geometric objects do have edges. A closed interval \([a, b] \subseteq
\mathbb{R}\) has its two endpoints. A closed disk in the plane has its bounding circle. A closed
hemisphere of the sphere \(\mathbb{S}^n\) terminates at an equatorial \((n-1)\)-sphere. At an
endpoint of \([a, b]\), no neighborhood inside the interval is homeomorphic to an open interval of
\(\mathbb{R}\). Every such neighborhood is a half-open interval, with the endpoint sitting on its
edge. These spaces are not manifolds in the sense developed so far, but they are manifolds in a
slightly enlarged sense, one that admits a boundary.
We develop this enlarged notion now, as the closing topic of the topological and smooth
foundations, because the boundary is precisely where the most important integral identities of
geometry live. The classical theorems of vector calculus all relate an integral over a region to
an integral over the edge of that region. Green's theorem in the plane, the divergence theorem of
Gauss and the curl theorem of Stokes are the familiar instances. Their common generalization, the
modern Stokes theorem, takes the form
\[
\int_{M} d\omega = \int_{\partial M} \omega,
\]
in which the left-hand side integrates over a manifold and the right-hand side integrates over its boundary
\(\partial M\). For this identity even to be stated, one needs a class of spaces that carry both a smooth
structure in their interior and a well-defined boundary on which the second integral makes sense.
The objects of this page are exactly those spaces. We do not develop integration here, since that
requires the machinery of differential forms, taken up later in the series. The present page
builds the stage on which it will be performed.
The need is not confined to classical analysis. Wherever a domain is constrained, a boundary
appears. Boundary-value problems for partial differential equations are posed on regions whose edges carry
the prescribed data, as in the Dirichlet and Neumann problems and in the free-boundary problems of
the calculus of variations. The integration theory we developed on the
measure-theoretic side has its natural geometric
counterpart on manifolds with boundary. The same structure recurs in machine learning and
robotics. A configuration space subject to constraints, such as joint angle limits on an
articulated arm or obstacle-avoidance regions in a planning problem, is a manifold with boundary
rather than a boundaryless one. The
variational autoencoder page's robotic manipulation demonstration
parametrizes a three-degree-of-freedom arm by a triple of joint angles, and it implicitly works
over such a constrained space. The admissible joint angles fill a product of closed intervals
\([\theta_{\min}, \theta_{\max}]^3\). Strictly, a product of closed intervals has corners as well
as faces, which places it in the slightly larger class of manifolds with corners. The
manifold series treats that class much later. For now we record only that boundaries are the rule,
not the exception, once domains are constrained.
The Upper Half-Space
Just as a boundaryless \(n\)-manifold is modeled locally on \(\mathbb{R}^n\), a manifold with boundary is modeled
locally on a half-space: the points of \(\mathbb{R}^n\) lying on one side of a hyperplane, together with the
hyperplane itself. Fixing the last coordinate as the one cut off, we obtain the standard local model.
Definition: Closed Upper Half-Space
For \(n \ge 1\), the closed upper half-space \(\mathbb{H}^n \subseteq \mathbb{R}^n\) is the set
\[
\mathbb{H}^n = \bigl\{ (x^1, \ldots, x^n) \in \mathbb{R}^n : x^n \ge 0 \bigr\},
\]
equipped with the subspace topology inherited from \(\mathbb{R}^n\). For \(n = 0\), we set
\(\mathbb{H}^0 = \mathbb{R}^0 = \{0\}\).
The half-space inherits two distinguished subsets from the position of a point relative to the bounding hyperplane.
For \(n \ge 1\), the interior of the half-space consists of the points lying strictly off the
hyperplane,
\[
\operatorname{Int} \mathbb{H}^n = \bigl\{ (x^1, \ldots, x^n) : x^n \gt 0 \bigr\},
\]
and the boundary of the half-space consists of the points lying on it,
\[
\partial \mathbb{H}^n = \bigl\{ (x^1, \ldots, x^n) : x^n = 0 \bigr\}.
\]
The interior \(\operatorname{Int} \mathbb{H}^n\) is an open subset of \(\mathbb{R}^n\), and it is exactly the
topological interior of \(\mathbb{H}^n\) as a subset of \(\mathbb{R}^n\). The boundary
\(\partial \mathbb{H}^n\) is the hyperplane \(\{x^n = 0\}\). Discarding the final
coordinate identifies it with \(\mathbb{R}^{n-1}\), so it is an \((n-1)\)-dimensional Euclidean
space sitting inside \(\mathbb{R}^n\). The degenerate case \(n = 0\) follows the convention above.
Here \(\mathbb{H}^0 = \{0\}\) is a single point with \(\operatorname{Int} \mathbb{H}^0 = \{0\}\)
and \(\partial \mathbb{H}^0 = \varnothing\).
The symbols \(\operatorname{Int}\) and \(\partial\) call for a word of caution, and we return to
it once manifolds enter the picture. As written here, \(\operatorname{Int} \mathbb{H}^n\) and
\(\partial \mathbb{H}^n\) are defined by an inequality on the coordinate \(x^n\). They are subsets
of \(\mathbb{R}^n\) singled out by their position relative to the hyperplane, and this is the
description we use as a local model. A separate matter remains, and it is the central
subtlety of the next section. The interior and boundary of an abstract manifold are defined
intrinsically, without reference to any ambient space, and we must ask whether they can be
detected chart by chart through this model. That they can is the content of an invariance theorem.
Until it is established we keep the half-space picture and the manifold picture notationally
distinct.
Topological Manifolds with Boundary
With the local model in hand, the definition of a manifold with boundary is obtained from the
boundaryless definition by a single change. A neighborhood of a point is now permitted to look
like an open subset of the half-space \(\mathbb{H}^n\), not only an open subset of
\(\mathbb{R}^n\). The Hausdorff and second-countability requirements are unchanged.
Definition: Topological Manifold with Boundary
A topological \(n\)-manifold with boundary is a topological space \(M\) that is
-
Hausdorff
and
second-countable,
and
-
locally Euclidean with boundary: every point \(p \in M\) has an open
neighborhood homeomorphic either to an open subset of \(\mathbb{R}^n\) or to an open subset of
the half-space \(\mathbb{H}^n\).
The phrase "with boundary" is a permission, not a requirement. A point whose neighborhood happens
to be homeomorphic to an open subset of \(\mathbb{R}^n\) is admitted exactly as before. Every
boundaryless \(n\)-manifold is therefore a manifold with boundary in which the boundary turns out
to be empty. We will be able to make that statement precise once the boundary is defined. The
definition deliberately enlarges the class of admissible spaces instead of replacing one
class with another.
Charts and Their Two Types
The chart vocabulary carries over verbatim, with the codomain now allowed to lie in either model space.
Definition: Chart for a Manifold with Boundary
Let \(M\) be a topological \(n\)-manifold with boundary. A chart for \(M\) is a pair
\((U, \varphi)\) where \(U \subseteq M\) is open and \(\varphi\) is a homeomorphism from \(U\) onto
an open subset \(\varphi(U)\) of either \(\mathbb{R}^n\) or \(\mathbb{H}^n\).
Charts split into two kinds according to where their image sits relative to the bounding hyperplane of the
model. The distinction is the engine of the entire theory of the boundary.
Definition: Interior Chart and Boundary Chart
Let \((U, \varphi)\) be a chart for a topological \(n\)-manifold with boundary \(M\).
-
\((U, \varphi)\) is an interior chart if \(\varphi(U)\) is an open subset
of \(\mathbb{R}^n\). This covers the case in which \(\varphi(U)\) is an open subset of
\(\mathbb{H}^n\) disjoint from \(\partial \mathbb{H}^n\), since such a set is also open in
\(\mathbb{R}^n\).
-
\((U, \varphi)\) is a boundary chart if \(\varphi(U)\) is an open subset of
\(\mathbb{H}^n\) with \(\varphi(U) \cap \partial \mathbb{H}^n \ne \varnothing\).
A single subtlety deserves emphasis. By definition of the subspace topology, an open subset of
\(\mathbb{H}^n\) that misses the hyperplane \(\partial \mathbb{H}^n\) is an open subset of
\(\mathbb{R}^n\) as well. A chart with such an image is therefore an interior chart, even when the
half-space was the model we had in mind when writing it down. The classification into interior and
boundary charts is exclusive and exhaustive. A chart image that lies in \(\mathbb{H}^n\) and meets
\(\partial \mathbb{H}^n\) is never open in \(\mathbb{R}^n\), and every chart image is of one kind or
the other. It is precisely the points carried onto \(\partial \mathbb{H}^n\) by some chart
that we are about to single out.
The codomain of a boundary chart often has a standard convenient shape, the half-space analogue of a
coordinate ball.
Definition: Coordinate Half-Ball
A coordinate half-ball is a boundary chart \((U, \varphi)\) whose image is a set of
the form \(B_r(x_0) \cap \mathbb{H}^n\), where \(x_0 \in \partial \mathbb{H}^n\) and \(B_r(x_0)\) is
the open ball of radius \(r\) centered at \(x_0\) in \(\mathbb{R}^n\). Equivalently,
\(\varphi(U)\) is an open ball in \(\mathbb{R}^n\) centered on the hyperplane, intersected
with the half-space.
Interior and Boundary Points
We can now define, intrinsically on \(M\), the two classes of points that the half-space model
distinguishes locally.
Definition: Interior Point, Boundary Point, \(\operatorname{Int} M\), \(\partial M\)
Let \(M\) be a topological \(n\)-manifold with boundary, and let \(p \in M\).
-
\(p\) is an interior point of \(M\) if it lies in the domain of some interior
chart, or in the domain of a boundary chart \((U, \varphi)\) with
\(\varphi(p) \in \operatorname{Int} \mathbb{H}^n\).
-
\(p\) is a boundary point of \(M\) if it lies in the domain of some boundary
chart \((U, \varphi)\) with \(\varphi(p) \in \partial \mathbb{H}^n\).
The set of all boundary points is the boundary of \(M\), denoted \(\partial
M\). The set of all interior points is the interior of \(M\), denoted
\(\operatorname{Int} M\).
The definitions are phrased existentially, in terms of lying in the domain of some chart
of the stated kind, and this is exactly where a difficulty hides. A given point \(p\) may lie in the domains of
many charts at once. Nothing in the definitions, as stated, forbids one chart from presenting \(p\) as an
interior point while another presents the same \(p\) as a boundary point. Were that to happen, the labels
"interior" and "boundary" would not be properties of the point at all, but artifacts of the chart chosen to
view it, and the sets \(\operatorname{Int} M\) and \(\partial M\) would be ill-defined. A theorem
rules this out and shows that the two classes are genuinely intrinsic.
Theorem: Topological Invariance of the Boundary
Let \(M\) be a topological \(n\)-manifold with boundary. No point of \(M\) is simultaneously an interior
point and a boundary point. Consequently \(\operatorname{Int} M\) and \(\partial M\) are disjoint, and
every point of \(M\) belongs to exactly one of them, so that
\[
M = \operatorname{Int} M \sqcup \partial M.
\]
We state this result without proof. The obstruction is genuine. At the purely topological level,
the assertion that an open subset of \(\mathbb{R}^n\) cannot be homeomorphic to a neighborhood of
a point on the edge of \(\mathbb{H}^n\) is a statement about the local topology of Euclidean
space, and it lies beyond what point-set methods can reach. The standard proof uses the machinery
of singular homology, and in particular the local homology groups that distinguish a point of
\(\operatorname{Int} \mathbb{H}^n\) from a point of \(\partial \mathbb{H}^n\). That machinery is
outside the scope of the manifold series at this stage. Remarkably, once a smooth
structure is available, the same invariance can be proved by elementary calculus with no algebraic
topology at all. That smooth counterpart is the technical climax of this page. One proof requires
homology and the other requires only the chain rule, and the contrast between them is one of the
instructive lessons of the subject.
Two Meanings of the Symbol \(\partial\)
The notation \(\partial M\) collides with another standard use of the same symbol, and the two must be kept
apart. In point-set topology, when a space \(X\) sits inside an ambient space, the topological boundary
of \(X\) is the set of points in the closure of \(X\) that are not in its topological interior.
These are the points that touch both \(X\) and its complement. The manifold boundary just
defined is an intrinsic notion. It depends only on \(M\) as an abstract manifold and not on any
embedding into a larger space. The two need not
coincide, and conflating them is a common source of error.
The closed half-space and the closed unit ball illustrate the agreement, and an interval placed in
the plane illustrates the disagreement. Regarded as a manifold with boundary, \(\mathbb{H}^n\) has
manifold boundary \(\partial \mathbb{H}^n = \{x^n = 0\}\). Regarded as a subset of
\(\mathbb{R}^n\), its topological boundary is the same hyperplane, so here the two notions agree.
The closed unit ball \(\overline{\mathbb{B}}^n \subseteq \mathbb{R}^n\) is a manifold with
boundary whose manifold boundary is the unit sphere \(\mathbb{S}^{n-1}\), and its topological
boundary as a subset of \(\mathbb{R}^n\) is also \(\mathbb{S}^{n-1}\). The two agree again. But
the agreement is not automatic. It requires the manifold to sit in the ambient space as a closed
subset of the same dimension, and either condition can fail. The half-open interval \([0,1)\) inside
\(\mathbb{R}\) has manifold boundary \(\{0\}\) and topological boundary \(\{0, 1\}\), so a failure of
closedness alone already separates the two. The open interval \((0,1)\), viewed as a \(1\)-manifold,
has empty manifold boundary. Viewed as a subset of \(\mathbb{R}^2\) along the \(x\)-axis, it has
empty topological interior and closure \([0,1] \times \{0\}\), so every one of its points is a
topological boundary point. The
manifold boundary is the notion this page concerns, and the symbol \(\partial\) always refers to
it here.
Closed and Open Manifolds
Two further pieces of terminology, both concerning boundaryless manifolds, are conventional in the literature and
worth recording before they appear unannounced. Both invite confusion with the point-set vocabulary of open and
closed sets, and neither has anything to do with it.
Definition: Closed Manifold and Open Manifold
A closed manifold is a compact manifold without boundary. An open manifold
is a noncompact connected manifold without boundary.
The word "closed" here records compactness, not the topological property of being a closed set, and neither a
closed manifold nor an open manifold has any boundary at all. The sphere \(\mathbb{S}^n\) is a
closed manifold. The Euclidean space \(\mathbb{R}^n\) and the open ball are open manifolds. A
closed interval \([0,1]\), by contrast, is neither. It is compact but does have a boundary, so it
is a compact manifold with boundary and falls under none of this terminology. The terms are
useful precisely because the property of having no boundary, combined with a
compactness alternative, organizes much of the global theory of manifolds.
Topological Properties of Manifolds with Boundary
Granting the topological invariance of the boundary, the interior and the boundary of a manifold are
well-defined sets, and we can ask what kind of spaces they are in their own right. The answer is
the cleanest possible one. The interior is a boundaryless manifold of the same
dimension, and the boundary is a boundaryless manifold of one dimension lower. The statement also
records when the boundary is empty and what
happens in the degenerate dimension zero.
Proposition: Structure of the Interior and Boundary
Let \(M\) be a topological \(n\)-manifold with boundary.
-
\(\operatorname{Int} M\) is an open subset of \(M\) and a topological \(n\)-manifold without
boundary.
-
\(\partial M\) is a closed subset of \(M\), and for \(n \ge 1\) it is a topological
\((n-1)\)-manifold without boundary.
-
\(M\) is a topological manifold without boundary if and only if \(\partial M = \varnothing\).
-
If \(n = 0\), then \(\partial M = \varnothing\) and \(M\) is a \(0\)-manifold.
Proof:
(1):
Each interior point lies, by definition, in the domain of a chart carrying it into
\(\operatorname{Int} \mathbb{H}^n\) or into an open subset of \(\mathbb{R}^n\). Shrinking that
chart's domain to the preimage of a small open ball about the image point produces a
neighborhood of the point consisting entirely of interior points and homeomorphic to an open
subset of \(\mathbb{R}^n\). Hence \(\operatorname{Int} M\) is open in \(M\) and every one of
its points has a Euclidean neighborhood, so it is locally Euclidean without boundary. It
inherits the Hausdorff and second-countability properties from \(M\) as a subspace, and is
therefore a topological \(n\)-manifold without boundary.
(2):
Since \(\partial M = M \setminus \operatorname{Int} M\) by the invariance theorem, and
\(\operatorname{Int} M\) is open, \(\partial M\) is closed in \(M\). For the manifold structure, let
\(p \in \partial M\) lie in a boundary chart \((U, \varphi)\) with \(\varphi(p) \in \partial \mathbb{H}^n\).
Restricting \(\varphi\) to \(U \cap \partial M\) and composing with the identification
\(\partial \mathbb{H}^n \cong \mathbb{R}^{n-1}\) given by dropping the last coordinate yields a
homeomorphism from a neighborhood of \(p\) in \(\partial M\) onto an open subset of \(\mathbb{R}^{n-1}\).
These restricted charts cover \(\partial M\) and exhibit it as locally Euclidean of dimension
\(n-1\) without boundary. With the inherited Hausdorff and second-countability properties,
\(\partial M\) is a topological \((n-1)\)-manifold without boundary.
(3):
If \(\partial M = \varnothing\) then every point is interior, so \(M = \operatorname{Int} M\) is
boundaryless by (1). Conversely, a manifold without boundary has every point covered by a chart into
\(\mathbb{R}^n\), making every point interior and \(\partial M = \varnothing\).
(4):
A \(0\)-dimensional model space is a single point: \(\mathbb{R}^0 = \mathbb{H}^0 = \{0\}\), with
\(\partial \mathbb{H}^0 = \varnothing\) by convention. Every chart on a \(0\)-manifold therefore carries
its point into \(\operatorname{Int} \mathbb{H}^0\), so no point can be a boundary point and
\(\partial M = \varnothing\).
The relation \(\partial M = M \setminus \operatorname{Int} M\) used in part (2) is exactly the disjoint-union
decomposition supplied by the invariance theorem. Without that theorem, the complement of the
interior would not be guaranteed to consist of boundary points, and the closedness of \(\partial
M\) would not follow. This
is the one place in the elementary theory where the deferred topological invariance is genuinely needed.
Carrying the Topological Properties Across
The properties established earlier for boundaryless manifolds all survive the introduction of a
boundary. They include the existence of well-behaved bases, local compactness, paracompactness and
connectivity. The reason is structural. Each of those proofs rested on the local model being
Euclidean, and the half-space \(\mathbb{H}^n\) is just as well-behaved a local model as
\(\mathbb{R}^n\). Wherever a coordinate ball was used, a coordinate half-ball serves the same
purpose at boundary points, and the arguments are otherwise unchanged. We collect the results for
the record.
Proposition: Topological Properties with Boundary
Let \(M\) be a topological manifold with boundary. Then:
-
\(M\) has a countable basis of precompact coordinate balls and coordinate half-balls.
-
\(M\) is locally compact.
-
\(M\) is paracompact. More precisely, given an open cover \(\mathcal{U}\) of \(M\) and any
basis \(\mathcal{B}\) for the topology of \(M\), there exists a countable, locally finite
open refinement of \(\mathcal{U}\) consisting of elements of \(\mathcal{B}\).
-
\(M\) is locally path-connected.
-
\(M\) has countably many components, each of which is an open subset of \(M\) and a connected
topological manifold with boundary.
-
The fundamental group of \(M\) is countable.
Each statement is the boundary-aware version of a result proved for manifolds without boundary, and the
proofs require only the substitution of half-balls for balls at boundary points. Statement (1) refines the earlier
basis of precompact coordinate balls
by allowing half-balls in the cover. At boundary charts the single-chart construction in
\(\mathbb{R}^n\) is replaced by the identical construction inside \(\mathbb{H}^n\), and the
countable assembly is unchanged. Statement (2) follows from (1) exactly as before, since
local compactness
needs only one precompact neighborhood at each point, and half-balls are precompact. Statement (3),
paracompactness,
is deduced from the basis of (1) and local compactness by the same compact-exhaustion argument, which never
referred to the absence of boundary. Statements (4) and (5) are the
connectivity properties.
Coordinate half-balls, like coordinate balls, are path-connected, since a half-ball is convex and
path-connectedness transfers under the chart homeomorphism. The manifold therefore again has a
basis of path-connected open sets, and the component count is governed by second-countability just
as before.
Statement (6), the
countability of the fundamental group,
is of a different character from the rest. It is not a point-set consequence of the basis but a
fact about the algebraic topology of \(M\). Its proof for manifolds without boundary cuts a loop
into finitely many arcs, each confined to a simply connected coordinate ball, and reads off the
loop's class from the countable record of how consecutive arcs meet. Nothing in that argument uses
the absence of a boundary. Coordinate half-balls are convex, hence simply connected, and the cover
by half-balls is countable piece by piece exactly as the cover by balls. The same proof therefore
applies verbatim, with half-balls substituted for balls at boundary charts, and \(\pi_1(M)\) is
countable for a manifold with boundary as well.
Smooth Structures on Manifolds with Boundary
Everything so far has been topological. To do calculus on a manifold with boundary we repeat the construction
that produced
smooth manifolds
from topological ones. We single out a maximal atlas whose transition maps are diffeomorphisms.
There is exactly one new ingredient. Transition maps between boundary charts are maps between open subsets of the half-space
\(\mathbb{H}^n\), not of \(\mathbb{R}^n\), and the
Euclidean
definition of smoothness
we already have applies only to maps on open subsets of \(\mathbb{R}^n\). A subset of \(\mathbb{H}^n\) that meets
the boundary hyperplane is not open in \(\mathbb{R}^n\), so before anything else we must say what it means for a
map defined on such a set to be smooth.
Smoothness on Subsets of the Half-Space
The difficulty is that partial derivatives at a boundary point would have to be one-sided in the last variable,
and a one-sided derivative is a weaker object than a genuine derivative. It sees only the values
of the function on one side. The standard remedy declares a map smooth on a half-space subset exactly when it is the restriction
of an honestly smooth map defined on a full Euclidean neighborhood.
Definition: Smoothness on a Subset of \(\mathbb{H}^n\)
Let \(U \subseteq \mathbb{H}^n\) be open in the subspace topology, and let \(F : U \to \mathbb{R}^k\). The map
\(F\) is smooth if for every point \(x \in U\) there exist an open set
\(\widetilde{U} \subseteq \mathbb{R}^n\) containing \(x\) and a smooth map
\(\widetilde{F} : \widetilde{U} \to \mathbb{R}^k\), in the
ordinary Euclidean sense,
that agrees with \(F\) on \(\widetilde{U} \cap U\).
At points of \(U\) lying in \(\operatorname{Int} \mathbb{H}^n\) the condition is automatic and
adds nothing. Such a point already has a full neighborhood inside \(U\), and \(F\) is its own
extension there. The definition has content only at boundary points of \(U\), where it demands
that \(F\) extend smoothly across the hyperplane to one side. A commonly given alternative
description is that \(F\) is smooth on \(U\) precisely when all partial derivatives of
all orders exist throughout \(U\) and extend continuously up to the boundary. The one-sided
derivatives at boundary points then match the limits of the interior derivatives. That the two
descriptions are equivalent is a nontrivial extension theorem, which we neither prove nor use.
We take the extension form as primary because it makes the chain rule
available without one-sided bookkeeping.
That the extension requirement is a genuine restriction, not a formality satisfied by every continuous-looking
function, is shown by a single example. Consider on the half-disk \(\mathbb{B}^2 \cap \mathbb{H}^2\)
the function
\[
g(x, y) = \sqrt{y}, \quad y \ge 0.
\]
It is continuous on its domain and infinitely differentiable at every interior point. But it is not smooth in the
sense just defined: its partial derivative with respect to \(y\),
\[
\frac{\partial g}{\partial y} = \frac{1}{2\sqrt{y}},
\]
diverges as \(y \to 0^+\), so no continuous extension of the \(y\)-derivative to the boundary
exists, and a fortiori no smooth extension of \(g\) to an open neighborhood of any boundary point
in \(\mathbb{R}^2\) can exist. Such an extension would have a finite \(y\)-derivative at the
boundary, which the blow-up forbids.
Smoothness up to the boundary is therefore a real constraint, exactly the one needed to keep the chain rule and
the Jacobian well-behaved at the edge.
Smooth Manifolds with Boundary
With smoothness defined on half-space subsets, the compatibility of charts is defined exactly as
before. A transition map between two charts of a manifold with boundary is a homeomorphism between open
subsets of model spaces, each of which is either \(\mathbb{R}^n\) or \(\mathbb{H}^n\). The
half-space notion of smoothness applies to it in every case, so we may ask whether it is a
diffeomorphism in that sense, smooth with smooth inverse.
Definition: Smooth Manifold with Boundary
A smooth manifold with boundary is a topological manifold with boundary \(M\)
together with a maximal atlas of charts into \(\mathbb{R}^n\) or \(\mathbb{H}^n\) whose
members are pairwise smoothly compatible, meaning that the transition map of
any two is a diffeomorphism between the relevant open subsets of model spaces. Smoothness is
read in the half-space sense whenever a domain meets the boundary hyperplane. This maximal
atlas is the smooth structure on \(M\).
This is the
smooth structure
of the boundaryless theory with two adjustments and no others. A chart may now map into
\(\mathbb{H}^n\) as well as \(\mathbb{R}^n\), and the
smooth-compatibility condition
is read with the half-space notion of smoothness in place of the purely Euclidean one. Suppose no
chart meets the boundary, so that every transition is a map between open subsets of
\(\mathbb{R}^n\). The two readings then coincide and the definition reduces exactly to the
boundaryless one. A smooth manifold without boundary is thus the special case of a smooth manifold
with boundary in which \(\partial M = \varnothing\).
Smooth Charts and Half-Balls
The shape-based refinements of a chart specialize to the boundary setting in the obvious way, mirroring the
smooth coordinate balls
of the boundaryless theory.
Definition: Smooth Coordinate Half-Ball
Let \(M\) be a smooth manifold with boundary. A smooth coordinate half-ball
is a smooth chart \((U, \varphi)\), that is, an element of the smooth structure of \(M\),
whose image is of the form \(B_r(x_0) \cap \mathbb{H}^n\) with \(x_0 \in \partial
\mathbb{H}^n\).
Regular coordinate balls came from a packaging device: a ball sitting with compact closure inside
a strictly larger smooth chart. That packaging has a boundary version, in which the larger chart
is itself a half-ball.
Definition: Regular Coordinate Half-Ball
A subset \(B \subseteq M\) is a regular coordinate half-ball if there exist a smooth
coordinate half-ball \(B'\) with \(\overline{B} \subseteq B'\), a smooth coordinate map
\(\varphi : B' \to \mathbb{H}^n\), and radii \(r \lt r'\) with \(x_0 \in \partial \mathbb{H}^n\) such that
\[
\varphi(B) = B_r(x_0) \cap \mathbb{H}^n, \quad
\varphi(\overline{B}) = \overline{B_r(x_0)} \cap \mathbb{H}^n, \quad
\varphi(B') = B_{r'}(x_0) \cap \mathbb{H}^n.
\]
This is the half-space analogue of a
regular coordinate ball,
and like its boundaryless counterpart it is precompact in \(M\).
The basis result of the boundaryless theory persists as well.
Proposition: Basis of Regular Coordinate Balls and Half-Balls
Just as every smooth manifold has a
countable basis of regular coordinate balls,
every smooth manifold with boundary has a countable basis consisting of
regular coordinate balls at interior points and regular coordinate half-balls at boundary points.
The proof is the smooth refinement of the topological basis result of the previous section, adapted
exactly as the boundaryless basis-of-regular-balls argument was adapted from its topological
predecessor. Every chart in the construction is required to lie in the smooth structure, and at
boundary points the half-ball model replaces the ball. We will not rewrite that argument here, since
it differs from the one already given only by this substitution.
Open Submanifolds with Boundary
One further construction of the boundaryless theory carries over, and it is the one the pages
ahead will lean on most heavily. Passing to an open subset costs nothing, and it costs nothing at
the boundary either.
Definition: Open Submanifold with Boundary
Let \(M\) be a
smooth \(n\)-manifold with boundary
with smooth structure \(\mathcal{A}\), and let \(U \subseteq M\) be an open subset. The collection
\[
\mathcal{A}_U = \{(V, \varphi) \in \mathcal{A} : V \subseteq U\}
\]
is a smooth atlas on \(U\), and the smooth structure it determines makes \(U\) into a smooth
\(n\)-manifold with boundary, whose boundary is \(\partial U = U \cap \partial M\). Equipped
with the subspace topology and this smooth structure, \(U\) is called an open
submanifold with boundary of \(M\). When \(U \subseteq \operatorname{Int} M\) the
boundary of \(U\) is empty and \(U\) is an
open submanifold
in the earlier sense; in particular \(\operatorname{Int} M\) is an open submanifold of \(M\)
without boundary.
That \(U\) is a topological \(n\)-manifold with boundary is immediate. Hausdorffness and second
countability are inherited by subspaces, and a point of \(U\) has, inside \(U\), a neighborhood
modeled on an open subset of \(\mathbb{R}^n\) or of \(\mathbb{H}^n\), namely the intersection with
\(U\) of any chart domain around it.
The rest of the verification is the one already carried out in the boundaryless case. Every point
of \(U\) lies in the domain of some smooth chart \((W, \varphi)\) for
\(M\), and the restriction of that chart to \(W \cap U\) is smoothly compatible with every chart of
\(\mathcal{A}\), since each restricted transition map is an original transition map restricted to
an open subdomain. By maximality of \(\mathcal{A}\) the restricted chart belongs to
\(\mathcal{A}\), and since \(W \cap U \subseteq U\) it belongs to \(\mathcal{A}_U\). So the charts
of \(\mathcal{A}_U\) cover \(U\), and any two of them are smoothly compatible because they already
lie in \(\mathcal{A}\). The single new feature is that a restricted chart may be a boundary chart,
whose transitions are read in the
half-space sense;
that reading is stable under restriction to an open subdomain exactly as the Euclidean one is,
since a smooth extension across the hyperplane restricts to a smooth extension.
The identity \(\partial U = U \cap \partial M\) needs nothing beyond the description of
\(\mathcal{A}_U\). If \(p \in U\) is a boundary point of \(M\), some chart of \(\mathcal{A}\)
carries \(p\) into \(\partial \mathbb{H}^n\), and restricting that chart to its intersection with
\(U\) yields a chart of \(\mathcal{A}_U\) that does the same, so \(p\) is a boundary point of
\(U\). Conversely every chart of \(\mathcal{A}_U\) is a chart of \(\mathcal{A}\), so a boundary
point of \(U\) is a boundary point of \(M\). Shrinking a domain therefore neither manufactures nor
destroys boundary, and this is what makes open subsets a usable supply of smaller manifolds with
boundary: an argument that is local by nature may be run inside a single chart domain without
leaving the category.
Product and Smooth Invariance
Two results close the theory. The first records how the boundary behaves under products. The
second is the smooth counterpart of the invariance theorem stated earlier, and it is the technical
high point of the page. Where
the topological invariance required the machinery of algebraic topology, the smooth invariance falls to the chain
rule and a single fact about smooth maps with invertible derivative.
Products
Taking products of manifolds with boundary requires care, and the care is exactly the issue of corners. The
product of two closed half-lines is a closed quarter-plane, whose edge is not a smooth hypersurface but a pair of
rays meeting at a right angle. To stay within the category of manifolds with boundary, one must restrict products
so that at most one factor has a boundary.
Proposition: Products with a Single Boundary Factor
Let \(M_1, \ldots, M_k\) be smooth manifolds without boundary and let \(N\) be a smooth manifold with boundary.
Then the product \(M_1 \times \cdots \times M_k \times N\) is a smooth manifold with boundary, and
\[
\partial\bigl(M_1 \times \cdots \times M_k \times N\bigr) = M_1 \times \cdots \times M_k \times \partial N.
\]
Proof:
The smooth structure is built from product charts exactly as in the
boundaryless product construction,
with one factor's charts now allowed to be boundary charts into \(\mathbb{H}^m\). A product chart on
\(M_1 \times \cdots \times M_k \times N\) maps into
\(\mathbb{R}^{n_1} \times \cdots \times \mathbb{R}^{n_k} \times \mathbb{H}^m\), and the
identification \(\mathbb{R}^{n} \times \mathbb{H}^{m} \cong \mathbb{H}^{n+m}\),
obtained by placing the single half-space coordinate last, exhibits this product model space
as a half-space of the total dimension. Transition maps are products of the factor
transitions. Each factor transition is smooth, and a product of smooth maps between
(half-space) open sets is smooth in the half-space sense, so the product charts are smoothly
compatible and assemble into a smooth structure. A point of the product is a boundary point
precisely when its \(N\)-coordinate is carried to \(\partial \mathbb{H}^m\), that is,
precisely when the \(N\)-component lies in \(\partial N\). This is the displayed identity for
the boundary.
The single-boundary-factor restriction is essential, not a convenience. The product of two manifolds with boundary
has, along the locus where both boundaries meet, points whose neighborhoods are modeled on a product of two
half-spaces \(\mathbb{H}^n \times \mathbb{H}^m\) rather than on a single half-space. The obstruction is not
topological. The squaring map \(z \mapsto z^2\) of the complex plane carries the closed quarter-plane
homeomorphically onto the closed upper half-plane, so a corner can be flattened away by a homeomorphism. That map has vanishing
derivative at the origin, and no diffeomorphism flattens a corner. We do not prove that last fact
here, since it belongs to the theory of the objects that accommodate corners, the strictly
larger category of manifolds with corners, whose local model is the orthant \(\{x : x^1
\ge 0, \ldots, x^k \ge 0\}\). Their theory is developed much later in the manifold series, and it
is the proper setting for products such as the cube \([0,1]^n\) or the constrained joint-angle
spaces noted at the start of this page.
Smooth Invariance of the Boundary
We come to the theorem that gives the boundary of a smooth manifold its meaning. The interior and
boundary points were defined existentially, a point counting as a boundary point
if some boundary chart sends it to \(\partial \mathbb{H}^n\). The topological invariance
theorem guarantees that the labels are well-defined, and it was stated without proof because its
topological version needs singular homology. For smooth
manifolds the same conclusion is available by elementary means, and we prove it in full.
Theorem: Smooth Invariance of the Boundary
Let \(M\) be a smooth manifold with boundary and let \(p \in M\). If some smooth boundary chart
\((V, \varphi)\) for \(M\) has \(\varphi(p) \in \partial \mathbb{H}^n\), then every smooth chart whose domain
contains \(p\) is a boundary chart carrying \(p\) into \(\partial \mathbb{H}^n\). Equivalently, no point of
\(M\) is presented as a boundary point by one smooth chart and as an interior point by another, so
\(\operatorname{Int} M\) and \(\partial M\) are well-defined.
Proof:
The point \(p\) can be presented as an interior point in two ways, by an interior chart or by a boundary
chart \((U, \psi)\) with \(\psi(p) \in \operatorname{Int} \mathbb{H}^n\). The second way reduces to the
first. Replacing \(U\) by \(\psi^{-1}\bigl(\psi(U) \cap \operatorname{Int} \mathbb{H}^n\bigr)\)
leaves a chart whose image is open in \(\mathbb{R}^n\), and the restriction of a smooth chart to an
open subset is smoothly compatible with every chart, hence belongs to the maximal atlas. So we may
work with a smooth interior chart throughout.
Suppose, for contradiction, that \(p\) lies in the domain of a smooth interior chart \((U, \psi)\) and also in
the domain of a smooth boundary chart \((V, \varphi)\) with \(\varphi(p) \in \partial \mathbb{H}^n\). Let
\[
\tau = \varphi \circ \psi^{-1} : \psi(U \cap V) \to \varphi(U \cap V)
\]
be the transition map, a homeomorphism between open subsets of the model spaces. By smooth
compatibility of the two charts, both \(\tau\) and \(\tau^{-1}\) are smooth in the
half-space sense. Each agrees locally with a genuinely smooth map defined on an open subset of
\(\mathbb{R}^n\).
Write \(x_0 = \psi(p)\) and \(y_0 = \varphi(p) = \tau(x_0)\). Because \(\tau^{-1}\) is smooth at \(y_0\), there
is a neighborhood \(W\) of \(y_0\) in \(\mathbb{R}^n\) and a smooth map \(\eta : W \to \mathbb{R}^n\), in the
ordinary Euclidean sense, agreeing with \(\tau^{-1}\) on \(W \cap \varphi(U \cap V)\). On the other side, since
\((U, \psi)\) is an interior chart, \(\psi(U \cap V)\) is an open subset of \(\mathbb{R}^n\), so there is an
open Euclidean ball \(B\) centered at \(x_0\) and contained in \(\psi(U \cap V)\) on which \(\tau\) is
genuinely smooth. Shrinking \(B\) if necessary, we may assume \(B \subseteq \tau^{-1}(W)\).
On \(B\) the two maps compose to the identity:
\[
\eta \circ \tau\big|_{B} = \tau^{-1} \circ \tau\big|_{B} = \operatorname{id}_{B}.
\]
Differentiating with the chain rule at any \(x \in B\),
\[
D\eta\bigl(\tau(x)\bigr) \circ D\tau(x) = \operatorname{id},
\]
so the square matrix \(D\tau(x)\) has a left inverse and is therefore nonsingular at every \(x \in B\).
We now invoke the one analytic fact the argument needs, the open mapping property of
nonsingular smooth maps. A smooth map between open subsets of \(\mathbb{R}^n\) whose Jacobian
is nonsingular at every point is an open map, so it carries open sets to open sets. This is a
standard consequence of the inverse function theorem. Nonsingularity of the Jacobian makes the
map a local diffeomorphism at each point, and a local diffeomorphism is locally, hence
globally, open. Applying this to \(\tau\) on \(B\), we find that the image \(\tau(B)\) is an
open subset of \(\mathbb{R}^n\) containing \(y_0 = \varphi(p)\).
This is the contradiction. On the one hand \(\tau(B) \subseteq \varphi(U \cap V) \subseteq
\mathbb{H}^n\), so \(\tau(B)\) is a subset of the half-space. On the other hand \(\tau(B)\) is
open in \(\mathbb{R}^n\) and contains the point \(\varphi(p) \in \partial \mathbb{H}^n\). But
no subset of \(\mathbb{H}^n\) that is open in \(\mathbb{R}^n\) can contain a point of
\(\partial \mathbb{H}^n\). Any \(\mathbb{R}^n\)-open neighborhood of a point with final
coordinate \(x^n = 0\) contains points with \(x^n \lt 0\), which lie outside \(\mathbb{H}^n\).
The assumption that \(p\) is simultaneously an interior point and a boundary point is therefore untenable.
The contrast with the topological invariance theorem stated earlier is worth drawing explicitly, because it
illustrates a recurring theme. A smooth structure, once present, makes available tools far more
elementary than those the bare topology demands. The topological statement says that no
homeomorphism can identify a neighborhood of an interior point with a neighborhood of a boundary
point. It resists point-set methods and is proved through the local homology groups of singular
homology theory. The smooth statement just proved needs none of that. The transition map is
differentiable, its derivative is forced to be invertible by the chain rule, and invertibility of
the derivative is exactly the hypothesis under which a smooth map is open. Two routes of utterly
different cost thus reach the same geometric fact, that interior and boundary are intrinsic, and
the smooth route is the cheap one. This is one of the first concrete dividends of the smooth structure built over the
course of these pages, and it is the foundation on which the boundary integral of the next stage of the theory will
rest.